(4x^2+19x+16)/(x+3)

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Solution for (4x^2+19x+16)/(x+3) equation: 


D( x )

x+3 = 0

x+3 = 0

x+3 = 0

x+3 = 0 // - 3

x = -3

x in (-oo:-3) U (-3:+oo)

(4*x^2+19*x+16)/(x+3) = 0

4*x^2+19*x+16 = 0

4*x^2+19*x+16 = 0

DELTA = 19^2-(4*4*16)

DELTA = 105

DELTA > 0

x = (105^(1/2)-19)/(2*4) or x = (-105^(1/2)-19)/(2*4)

x = (105^(1/2)-19)/8 or x = (-(105^(1/2)+19))/8

(x+(105^(1/2)+19)/8)*(x-((105^(1/2)-19)/8)) = 0

((x+(105^(1/2)+19)/8)*(x-((105^(1/2)-19)/8)))/(x+3) = 0

( x+(105^(1/2)+19)/8 )

x+(105^(1/2)+19)/8 = 0 // - (105^(1/2)+19)/8

x = -((105^(1/2)+19)/8)

( x-((105^(1/2)-19)/8) )

x-((105^(1/2)-19)/8) = 0 // + (105^(1/2)-19)/8

x = (105^(1/2)-19)/8

x in { -((105^(1/2)+19)/8), (105^(1/2)-19)/8 }

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